Question

248 gm mixture containing Li2CO3 & CaCO3 on strong heating produces CO2(g), which exerts 3 atm pressure in a container of volume
24 L at temperature 27° C. The simplest mole ratio of Li2CO3 and CaCo3 in the mixture is x: 1. The value of x'is: [Given that R=0.08
L-atm/k-mole] [Atomic weight of Li = 7, Ca = 40]​

Answer 1

Answer:

CaCO

3

(s)⇌CaO(s)+CO

2

(g)

K

p

=p

CO

2

=3.9×10

−2

atm

Let the number of moles of CO

2

formed =n

n=

RT

p

CO

2

×V

=

0.082Latm/mol/K×1000K

3.9×10

−2

atm×0.654L

=3.11×10

−4

mol

The amount of CaO(s) formed will also be 3.11×10

−4

mol

The molecular weight of CaO=56g/mol

Hence, the mass of CaO formed =3.11×10

−4

mol×56g/mol=0.0174g