24g Mg metal reacts with water then calculate mole of H2 liberated
Answers
We first write the equation for the reaction as follows.
Mg(s) + 2H2O (l) —> Mg(OH)2 (aq) + H2 (g)
Molar mass of Magnesium is 24 g
The number of Magnesium moles is thus :
24/24 = 1 mole
The mole ratio of magnesium to Hydrogen is 1 : 1
Therefore 1 mole of Hydrogen gas is liberated.
The answer is thus 1 mole.
Answer:
The mole of H2 liberated is 1 mole
Explanation:
A mole is described as the quantity of a substance that includes precisely 6.02214076 X1023 simple entities of the given substance. A mole of a substance is mentioned the mass of a substance containing the equal range of essential devices as there are atoms in precisely 12.000 g of 12C.
Number of moles method is. Number of moles = Mass of substance / Mass of 1 mole. Number of moles = 95 / 86.94.
One mole of a substance has the equal mass in grams that one atom or molecule has in atomic mass devices
We first write the equation for the response as follows.
Mg(s) + 2H2O (l) —> Mg(OH)2 (aq) + H2 (g)
Molar mass of Magnesium is 24 g
The range of Magnesium moles is :
24/24 = 1 mole
The mole ratio of magnesium to Hydrogen is 1 : 1
Therefore 1 mole of Hydrogen fueloline is liberated.
The solution is 1 mole.
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