24g of N2 is allowed to react with 6g of h2 identify the limiting reagents
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Answer:
N2 is the limiting reagent.
Explanation:
because
1N2 + 3H2 ------> 2NH3
28g 6g 34g
from the above it is cleared that
when 28g N2 react with 6g H2 gives 34g NH3.
from unitry method,
28g N2 = 34g NH3
1g N2 = 34/28 × 1
24g N2 = 34/28 × 24
=29.1429 approx
Hence,N2 is the limiting agent
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