Question

(25)^2/5 X (729)^1/2 / (125)^1/3 X (27)^2/3 X (8)^4/3

Answer 1

\frac{ {25} }{5 x{729^1} } / \frac{2}{ {125^1} } / \frac{3x(27)^2}{3x(8)^4}/3
=\frac{25*3*3x(8)^4*3x(27)^2*(125)^1*2}{5x(729)^1}
= \frac{75*3x*4096*3x*729*125*2}{5x*729}
= \frac{76800000*3x*3x}{5x}
=(15360000*3*3x)
=46080000*3x----------------------(ans).

Answer 2

here you go bro this is your answer
{ {25} }{5 x{729^1} } / \frac{2}{ {125^1} } / \frac{3x(27)^2}{3x(8)^4}/3
={25*3*3x(8)^4*3x(27)^2*(125)^1*2}{5x(729)^1} 
= {75*3x*4096*3x*729*125*2}{5x*729} 
= {76800000*3x*3x}{5x}
=(15360000*3*3x)
=46080000*3x