Question

25. A body starts from rest with an acceleration of 2 m/s.
After 5 s, the direction of acceleration reverses again
for 5 s. The displacement is
(a) Om (b) 50 m (©) 55 m (d) 500 m​

Answer 1

Explanation:

u=o m/s

a=2 m/s^2

t=5 s

s= ut + 1/2 at^2

=0×5+1/2×2×5^2

=1/2×2×25

=25m

Answer 2

Answer:

25 m

Explanation:

Given,

Acceleration = 2 m/s²

Time = 5 s

By using the formula of the second equation of motion.

s = ut + 1/2 at²

Or you can use another formula which very easy to get distance or displacement.

If u = 0

So, s = 1/2 at² where u = 0

As we know that, a body starts from rest. So, u = 0 m/s.

=> s = 0 × 5 + 1/2 × 2 × 5²

=> s = 0 + 1/2 × 2 × 5²

=> s = 0 + 1/2 × 2 × 25

=> s = 0 + 0.5 × 50

=> s = 25 m

.°. s = 25 m