25. A cricket ball of mass 7 kg moving with a velocity of
0.5m/s is stopped by a player in 0.5s. What is the force
applied by the player to stop the ball ? b. In a cricket match
why does a player lowers his hands slightly while catching
the ball? c. Two cars have masses in the ratio 4:5,
accelerates in the ratio 2:3 .Find the ratio of the force
exerted by each of them
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Answer:
the answers are as follows.
Explanation:
the force excerted by ball on hand is m×v/t which is momentum by time. ie 7×0.5/0.5 so as reaction force he applies same force to take the ball into rest. second one the player lowers hand after catching ball to increase time of ball in this hand because the force is inversely propotional to time. and 3rd one the ratio of forces is 4×2 : 5×3 as force is equal to mass × acceleration.
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