Question

25. A particle starts moving with acceleration 2 m/s.
Distance travelled by it in 5th half second is -1
(1) 1.25 m (2) 2.25 m
(3) 6.25 m (4) 30.25 m

Answer 1

Hey Mate,
Sth= St-S(t-1),
S5th=S5/2-S2,
use S=ut+1/2at^2, u=0,a=2m/s^2, t= 2.5 and 2 sec respectively....
S5th=6.25-4,
S5th=2.25m.
Hence, b is correct.
Hope it helps uhh....!!!
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