Question

25. Calculate critical temperature of a metal if Hc=105A/m at 8K and 2x105A/m at 0K.​

Answer 1

Answer:

Critical Temperature, $T_c=11.304 K$

Explanation:

$H_c=105 A/m,H_0=2*105 A/m,T=8K,T_c=?$

$H_c=H_0(1-(\frac{T}{T_c} )^2)\\\\=>\frac{H_c}{H_0}= (1-(\frac{T}{T_c} )^2)\\\\=>(\frac{T}{T_c} )^2)=1-\frac{H_c}{H_0}\\\\=>T_c^2=\frac{T^2}{1-\frac{H_c}{H_0}}\\\\ =>T_c^2=\frac{8^2}{1-\frac{105}{2*105} } \\\\=>T_c^2=2*8^2\\\\=>T_c^2=128\\\\=>T_c=11.304 K$