25. Calculate the steady current through
the 2ohm resistor in the circuit shown in
the figure below.
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Answers
Answered by
0
Answer:
Effective resistance,R
12
=
2
1
+
3
1
=
6
5
R
12
=1.2Ω
resistance,R
12
is in series 2.8Ω
Total resistance =1.2+2.8=4.0Ω
Current,I=
4
6
=1.5A
Potential difference,AB=1.5×1.2=1.8V
Current through 2Ω=
2
1.8
=0.9A.
Answered by
1
Answer:
I1 = 0.9A
Explanation:
Total resistance of circuit is
R = { ( 2*3 ) /(2+3 ) } + 2.8 neglecting 2uf and 4 omh as they are in parallel
=4 ohm
hence total current in circuit is
I = E / R
= 6 / 4 = 1.5 A
Hence, P D across parallel combination of 2Ω and 3Ω resistances.
V' = IR' =1.5 x 1.2 = 1.8V
thus, Current in R1 = 2Ω resistance is given by,
I1 = V'/R1 = 1.8/2 = 0.9A
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