25. Construct an equilateral triangle PQR of side 5 cm.
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Answer:
Draw a line segment QR = 5 cm.
With Q as centre and radius = PQ = 5 cm, draw an arc.
Join PQ and PR to obtain ΔPQR.
Below QR, construct an acute ∠RQX.
Join Q7R.
Draw Q6R' || Q7R.
From R' draw R'P' || RP.
Hence, P'QR' is the required triangle.
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