Question

25. Find the LCM of x4– 1 , x2– 2x + 1

Answer 1

Answer:

(x-1)..............

Answer 2

Answer:

x⁴ - 1

= (x²)² - (1)²

= (x² + 1) (x² - 1)

= (x² + 1) (x + 1) (x - 1)

x2-x2+1

X(x-1)+1(x-1)

(x-1) (x+1)