25 g of an aqueous solution contains 15g of
urea. What is the conc. of the solution in terms
of molality (m) ( molecular mass of urea is 60 g
mol–1)
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1
Answer:
10 m
Explanation:
molality (m) = no.of moles / mass of solution in kg
moles = given mass / molar mass
so,, moles of urea= 15g/ 60g
= 1/4 mol
mass of solution in kg= 25g/ 1000
1/ 40kg
so,, m = n/ mass (kg)
= (1/4) /(1/40)
= 40/ 4
= 10 m
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