25 g of ethylene glycol is present in 100 g of water the solution `c kf for h2o is 1.86 the amount of ice separated on cooling is
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hello friend
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Here is ur answer
=> Given
ethylene glycol = 25 gm
kf=1.86
ΔTf=kf×m
where m= morality of solⁿ
let Tf =9.3°c
ΔTf=1.86×25×1000/w×62
9.3=1.86×25×1000/w×62
w=1.86×25×1000/9.3×62
w=80.6
∴ The mass of ice separated from H₂O =100-80.6 =19.4 gm
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hope it's help u
--------------------------------------------------------------------------------
Here is ur answer
=> Given
ethylene glycol = 25 gm
kf=1.86
ΔTf=kf×m
where m= morality of solⁿ
let Tf =9.3°c
ΔTf=1.86×25×1000/w×62
9.3=1.86×25×1000/w×62
w=1.86×25×1000/9.3×62
w=80.6
∴ The mass of ice separated from H₂O =100-80.6 =19.4 gm
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hope it's help u
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