Question

25. In Fig. 14.53, PQ is the diameter of the circle whose centre is O. Given angleROS = 42°. Calculate angleRTS​

Answer 1

Step-by-step explanation:

Join PS.

PQ is a diameter.

⇒ PSQ=90

o

[ Angle inscribe in a semicircle ]

⇒ ∠PSQ+∠PST=180

o

[ Linear pair ]

⇒ 90

o

+∠PST=180

o

⇒ ∠PST=90

o

∴ ∠SPT=

2

1

∠ROS

⇒ ∠SPT=

2

1

×42

o

∴ ∠SPT=21

o

In △PST,

⇒ ∠SPT+∠PTS+∠PST=180

o

⇒ 21

o

+∠PTS+90

o

=180

o

⇒ ∠PTS=180

o

−90

o

−21

o

⇒ ∠PTS=69

o

∴ ∠PTS=∠RTS=69

o

Answer 2

Answer:

555

$\times 362962 \times 359 \times$