Question

25 into 10 to the power 20 molecules of acetic acid are present in

Answer 1

Answer:

Volume = 500 mL = 0.500 L

Concentration = Moles / volume (L)

Plug the given values in the formula:

Concentration = 0.001 moles / 0.500 L

Concentration = 0.002 M

Hence 6.025 \times 10^{20} molecules of ‘acetic acid’ are present in 500 ml of its solution the ‘concentration of solution’ is 0.002 M.