25 mL 0.1 N H2SO4 neutralized with 20 mL xN Na2CO3. What will be the g/liter of Na2CO3 ?
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It neutralizes 20 mL of 0.04 N of HCl. The gram equivalent of 0.04 N HCl is1. 46 g. Therefore the volume of 0.5 N of Na2CO3 is 500 mL or one-half liter.
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Ur answer is 500mL or half litre .
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