25 ml of 0.4M solution is dilluted in water of volume 600 ml the new concentration will ne
Answers
Answered by
0
Answer:0.0167M
Explanation:Using the dilution factor.
C1V1=C2V2
Making C2 subject
C2=C1V1/V2
C1= 0.4M
V1=25ml
V2=600ml
C2=0.4M*25ml/600ml
C2=0.016667M
C2=0.0167M
Similar questions