Chemistry, asked by kunal8832, 8 months ago

25 ml of 0.4M solution is dilluted in water of volume 600 ml the new concentration will ne

Answers

Answered by akotoebenezer

0

Answer:0.0167M

Explanation:Using the dilution factor.

C1V1=C2V2

Making C2 subject

C2=C1V1/V2

C1= 0.4M

V1=25ml

V2=600ml

C2=0.4M*25ml/600ml

C2=0.016667M

C2=0.0167M

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