25 mL of 2N HCl and Xml of 2 N H2SO4 are mixed together and this acid mixture completely reacted with 250 ml of a<br />1N Na2CO3 solution. The value of x is :
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Answered by
6
Answer:
Explanation:
No of milimoles of H+ in Hcl= 25*2= 50
No of milimoles of H+ in H2so4= x*2= 2x
No of milimoles of OH- in na2co3=250*1=250
Atp
50+2x=250
Therefore x=100 ml
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Answered by
1
Answer:
Since 2N HCl hence to calculate the number of milimoles of H+ by volume*normality which in this case is 25*2 = 50millimoles.
As there is 2N H2SO4 then the number of millimoles of H+ of the acid is again by using the formulae = 2 * X (since in the question X ml of H2SO4 is given).
Mixing of the acid together will result in the mixture to be 250 millimoles hence by equating both we will find Xml.
2X + 50 = 250.
2X=200.
X=100mL.
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