Question

25 ml of 3.0 M HCI are mixed with 75 mL Of 4.0 M HCl. If the volumes
are additive, the molarity of the final mixture will be. [Ans. 3.75 M)​

Answer 1

Answer:

3. 75 M

Explanation:

Molarity ( M ) = no. of moles of solvent/volume of solution( in litres)

M1 = 3

or 3 = n1/0.025

n1 = 0.075 moles

M2 = 4

or 4 = n2/0.075

or n2= 0.3 moles

Therefore, total no. of moles of HCl in final solution = n1 + n2 = 0.075 + 0.3 = 0.375 moles

Volume of final solution = 25 ml + 75 ml = 100 ml = 0.1 L

M = 0.375/0.1 = 3.75 M

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