25 ml of hcl librates 10 ml of CO2 at ntp when reacting with excess of caco3 the normality of hcl be
Answers
Answer:
(ii) Volume strength of H O = 5.6 x Normality of H O ... The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl and 250 ... treating 25 g of this sample with excess of dil HCI.
The Normality Of HCl Is 0.03 N
GIVEN
The volume of HCl = 25 ml
the volume of CO₂ formed = 10 ml
TO FIND
Normality of HCl
SOLUTION
We can solve the above problem as follows -
We know that,
Normality = Molarity × n-factor
Where,
n-factor = number of replaceable hydrogen ions ( in case of an acid)
To find the normality of HCl, let us first write the chemical formula and find the molarity of HCl.
CaCO₃ + 2HCl ------------> CaCl₂ + CO₂ + H₂O
The volume of Carbon dioxide gas formed = 10 ml at Ntp
10 mL = 0.01L
we know,
1 mole of gas occupies 22.4 L at Ntp
so,
Now, From the above reaction, we can say that -
Moles of HCl = 2 × moles of CO₂
so,
Moles of HCl = 2× 4.4×10⁻⁴ = 8.8 × 10⁻⁴ moles.
Molarity = Moles of solute /volume of solute in 1 liter
Therefore,
= 0.03 M
Now,
We know that the n-factor of HCl is 1
So, Normality = Molarity = 0.03
Hence, the Normality of HCl is 0.03 N
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