25. plz solve it
plzzzzzz
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1
Hey!!!!
Good Afternoon
___________
let the speed of the train be x km/h
Then we know
=> time = distance/speed
ATQ,
Cross Multiplying
=> x² - 8x - 1280 = 0
=> x² - 40x + 32x - 1280 = 0
=> x(x - 40) + 32(x - 40) = 0
=> (x - 40)(x + 32) = 0
Thus x = 40 km/h
Thus the speed of the train is 40 km/h
_______________
Hope this helps ✌️
For doubts comment below
Good Afternoon
___________
let the speed of the train be x km/h
Then we know
=> time = distance/speed
ATQ,
Cross Multiplying
=> x² - 8x - 1280 = 0
=> x² - 40x + 32x - 1280 = 0
=> x(x - 40) + 32(x - 40) = 0
=> (x - 40)(x + 32) = 0
Thus x = 40 km/h
Thus the speed of the train is 40 km/h
_______________
Hope this helps ✌️
For doubts comment below
Answered by
1
let the speed =x
let the time =t
x=v/t , t=v/s
x=480/t , t=480/x
let the time =t
x=v/t , t=v/s
x=480/t , t=480/x
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