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Final Answer : n = 0.
Steps :
1) Using Dimensional Techniques :
We know that
dim(sin-1(f(x)) = dimensionless = constant.
dim(dx) = dim(x).
2) Rules of Dimension :
Quantities having same dimension are added or subtracted.
Here, x/a - 1. implies x/a is constant
=> dim(x) = dim(a).
Using this,
Given expression has same dimensions in both sides.
dim(x/√x^2) = dim( a^n * sin-1(x/a-1)
=> dim(x/x) = dim(a^n)
since dim(sin-1( ) ) is dimensionless
=> dimensionless = dim(a^n)
=> n= 0.
For Calculation see pic.
Steps :
1) Using Dimensional Techniques :
We know that
dim(sin-1(f(x)) = dimensionless = constant.
dim(dx) = dim(x).
2) Rules of Dimension :
Quantities having same dimension are added or subtracted.
Here, x/a - 1. implies x/a is constant
=> dim(x) = dim(a).
Using this,
Given expression has same dimensions in both sides.
dim(x/√x^2) = dim( a^n * sin-1(x/a-1)
=> dim(x/x) = dim(a^n)
since dim(sin-1( ) ) is dimensionless
=> dimensionless = dim(a^n)
=> n= 0.
For Calculation see pic.
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JinKazama1:
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Answered by
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Hey mate......
here's ur answer......
Option A ......
Hope it helps ☺️❤️
here's ur answer......
Option A ......
Hope it helps ☺️❤️
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