Question

25 POINTS.......
SEE THE ATTACHMENT.

STATE WHICH TYPE OF TRIANGLE

UNRELATED ANSWERS WILL BE REPORTED

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Answer 1

Let point A = ( 2,0 ), B = ( - 2, 0 ) and C = ( 0,2 ).

Distance between AB =

$\sqrt{{(-2\:-\:2)}^{2}\:+\:{(0\:-\:0)}^{2}}$

AB = $\sqrt{16}$

AB = 4 units

Distance between BC =

$\sqrt{{(0\:+\:2)}^{2}\:+\:{(2\:-\:0)}^{2}}$

BC = $\sqrt{4\:+\:4}$

BC = $\sqrt{8}$

BC = 2$\sqrt{2}$ units.

Distance between AC =

$\sqrt{{(0\:-\:2)}^{2}\:+\:{(2\:-\:0)}^{2}}$

AC = $\sqrt{4\: + \:4}$

AC = $\sqrt{8}$

AC = 2$\sqrt{2}$ units.

Since, BC = AC = 2$\sqrt{2}$ units.

Two sides are equal. So, it is an $\tt{Isosceles \:triangle}$.

Answer 2

It is an isosceles triangle