Question

25. Show that (a-b)(a+b) + (b-c)(b+c) + (c-a)(c+a) = 0​

Answer 1

Answer:

hence prove

Step-by-step explanation:

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)

as we know (a-b)(a+b)=a^2-b^2

so,

= a^2-b^2+b^2-c^2+c^2-a^2

= 0