Question

25) The population of a city decreased from 25,000 to 24,000. Find the percentage decrease.​

Answer 1

Answer:

The population decreased is 4%.

Answer 2

Answer:

Percent decrease is 4%.

Step-by-step explanation:

As per the provided information in the given question, we have,

• The population of a city decreased from 25,000 to 24,000.

We are asked to calculate the percent decrease.

Since the population of the city decreased from 25,000 to 24,000 , so we can say that :

• Original population was 25,000.

★ A percent change in decrease given as a percent of the original amount.

$\longrightarrow \sf { \% \: decrease = \left \lgroup \dfrac{Amount_{(Decreased)}}{Original \: Amount} \times 100 \right \rgroup \: \% }$

† Calculating amount of decrease :

➝ Amount of decrease = Original population ― New population

➝ Amount of decrease = 25,000 – 24,000

➝ Amount of decrease = 1000

Now, we have :

• Amount of decrease = 1000
• Original amount of population = 25,000

Substituting the values in the formula.

$\longrightarrow \sf { \% \: decrease = \left \lgroup \dfrac{1000}{25000} \times 100 \right \rgroup \: \% }$

Cancelling the zeros in the numerator and the denominator.

$\longrightarrow \sf { \% \: decrease = \left \lgroup \dfrac{1}{25} \times 100 \right \rgroup \: \% }$

Multiplying 1 with 100.

$\longrightarrow \sf { \% \: decrease =\left \lgroup \cancel{ \dfrac{100}{25} } \right \rgroup \: \%}$

Dividing 100 by 25.

$\longrightarrow \underline{\boxed{\sf { \% \: decrease = 4 \: \% }}}\; \bigstar$

Therefore, percent decrease is 4 %.

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★ Some related formulae :

• $\sf { \% \: decrease = \left \lgroup \dfrac{Amount_{(Decreased)}}{Original \: Amount} \times 100 \right \rgroup \: \% }$

• $\sf { \% \: increase = \left \lgroup \dfrac{Amount_{(Increased)}}{Original \: Amount} \times 100 \right \rgroup \: \% }$

• $\sf { \% \: error = \left \lgroup \dfrac{Error}{Actual \: value} \times 100 \right \rgroup \: \% }$