Math, asked by affu5557, 6 months ago

25. The present age of a father is 3 yr
than three times the age of his son.
three years later, father's age will be 10 yr
than twice the age of the son. The father
present age is
(a) 33yr
(b) 39yr
(c) 40yr

(c) 45 yr

Answers

Answered by BrainlyTornado
4

ANSWER:

  • The present age of father = 33.

GIVEN:

  • The present age of a father is 3 years more than three times the age of his son.

  • Three years later, father's age will be 10 years more than twice the age of the son.

TO FIND:

  • The father's present age.

EXPLANATION:

Let the present age of father be x.

Let the present age of son be y.

x = 3y + 3

x + 3 = 2(y + 3) + 10

Substitute x = 3y + 3

3y + 3 + 3 = 2(y + 3) + 10

3y + 3 + 3 = 2y + 6 + 10

3y + 3 + 3 = 2y + 16

3y + 6 = 2y + 16

y = 10

Substitute y = 10 in x = 3y + 3

x = 3(10) + 3

x = 33

x = 33

HENCE THE PRESENT AGE OF FATHER WILL BE 33.

VERIFICATION:

Substitute x = 33 and y = 10 in x = 3y + 3

33 = 3(10) + 3

33 = 33

Substitute x = 33 and y = 10 in x + 3 = 2(y + 3) + 10

33 + 3 = 2(10 + 3) + 10

36 = 2(13) + 10

36 = 26 + 10

36 = 36

HENCE VERIFIED.

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