Math, asked by shubhradip1234, 2 months ago

25. The value of (-2) 5 * (-3) (-2) × (-7)

Answers

Answered by wangarwarpraja94
1

Answer:

HOPE YOU UNDERSTAND

Step-by-step explanation:

Given:- 7^0 * (25)^-3/2-5^-3

Solution:-

{7}^{0} \times {(25)}^{ \frac{ - 3}{2} } - {(5)}^{ - 3}7

0

×(25)

2

−3

−(5)

−3

= 1 \times {(5 \times 5)}^{ \frac{ - 3}{2} } - {(5)}^{ - 3}=1×(5×5)

2

−3

−(5)

−3

[We know a^0=1]

= {( {5}^{2} )}^{ \frac{ - 3}{2} } - {(5)}^{ - 3}=(5

2

)

2

−3

−(5)

−3

= {(5)}^{2 \times (\frac{ - 3}{2}) } - {(5)}^{ - 3}=(5)

2×(

2

−3

)

−(5)

−3

= {(5)}^{ - 3} - {5}^{ - 3}=(5)

−3

−5

−3

we know that a^(-1) = (1/a)

= \frac{1}{ {5}^{3} } - \frac{1}{ {5}^{ 3} }=

5

3

1

5

3

1

= \frac{1 - 1}{ {5}^{3} }=

5

3

1−1

= \frac{1 - 1}{5 \times 5 \times 5}=

5×5×5

1−1

= \frac{0}{125}=

125

0

= 0=0

Because by the rule when we divided zero by any number the answer will be zero.

Hence, the value of 7^0 * (25)^-3/2-5^-3 is 0.(ans)

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