Question

25 tuning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce 3 beats/sec. If the frequency of the first turning fork is the octave of the last fork, then the frequency o​

Answer 1

Explanation:

Given 25 tuning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce 3 beats/sec. If the frequency of the first tuning fork is the octave of the last fork, then the frequency of the 21st fork is

• Let the frequency of the last tuning fork be a
• So the frequency of the first tuning fork will be 2a (since frequency of first tuning fork is octave of last fork)
• Now frequency of 2nd tuning fork will be 2a – 3 (since it produces 3 beats / sec)
• Similarly frequency of 3rd tuning fork will be 2a – 6
• So we get frequency of 25th tuning fork as 2a – (24)3
•                            So a = 2a – 72
•                          Or a = 72 hertz
• Now we need to find the frequency of the 21st tuning fork.
• So we get 2 a – (20) 3
•               2 (72) – 60
•                144 – 60
•                     84 hertz.  

Reference link will be

https://brainly.in/question/8038338