Question

25% water, 25% ethane, 25% acetic acid by mass find mole fraction

Answer 1

hlo mate here is ur ans............

Let the mass of solution is 100g

Then, mass of H2​O=25g

   mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =25/18g/mol​=1.4

Number of moles of ethanol =25/46g/mol=0.54

Number of moles of Acetic acid =50/60g/mol​=0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water =1.4/2.74​=0.51

      mole fraction of Ethanol =0.54/2.74​=0.197

      mole fraction of acetic acid =0.8/2.74​=0.291

hope this helps uh dear :)

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