Question

25^(x-3)(2x-3) =3125​

Answer 1

So the final answer is x=0 or x=4

hope this answer will help you

Answer 2

The solution is x=3.59,0.903.

Step-by-step explanation:

Given : Expression $25^{(x-3)(2x-3)} =3125$

To find : Simplify the expression ?

Solution :

We know that,

$3125=5^5$

$25=5^2$

Re-write expression as,

$5^{2(x-3)(2x-3)} =5^5$

Comparing the base power both side,

$2(2x^2-3x-6x+9)=5$

$4x^2-18x+18=5$

$4x^2-18x+18-5=0$

$4x^2-18x+13=0$

Applying quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=4, b=-18 and c=13

$x=\frac{-(-18)\pm\sqrt{(-18)^2-4(4)(13)}}{2(4)}$

$x=\frac{18\pm\sqrt{324-208}}{8}$

$x=\frac{18\pm\sqrt{116}}{8}$

$x=\frac{18+\sqrt{116}}{8},\frac{18-\sqrt{116}}{8}$

$x=3.59,0.903$

Therefore, the solution is x=3.59,0.903.

#Learn more

If 125 to the power x is equal to 3125 then X equal to

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