25 x cube y cube - 49 x y factorise
niral:
answer is xy(5xy-7)(5xy+7)
Answers
Answered by
49
25x^3y^3-49xy
=xy[25x^2y^2-49]
=xy[(5xy) ^2-7^2]
=xy[(5xy-7) ^2]
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Answered by
46
Answer:
Step-by-step explanation:
→ 5² × x³y³ - 7² × xy
→ xy (5²*x³y³ / xy - 7²*xy/xy
→ xy(5² × x^3-1 y^3-1 - (7²))
→ xy(25x²y² - 49)
→ xy(5² × x²y² - 7²)
→ xy((5xy)² -(7)²)
→ xy((5xy-7)(5xy+7))
→ xy(5xy-7)(5xy+7)
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