Question

25) X starts walking from the place 'A'. He walks 4 km East
and reaches place 'B', then turns right. After going 3 km
straight he stops at the place 'C'. What is the shortest
distance between 'A' and 'C'?
A) 4 km
B) 5 km
C) 6 km
D) 7 km​

Answer 1

Step-by-step explanation:

By pythagoras theorem,

AB² + BC² = AC²

AC² = (4)² + (3)² = 16 + 9 = 25

AC = 5KM

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Answer 2

Answer:

AC=5km

Step-by-step explanation:

AB= 4km , BC= 3km , AC=?

Since this forms a right angled triangle we can use Pythagorean theorem

$4^{2} +3^{2} = ?^{2}$

= 16+9=$?^{2}$

= 25 =$?^{2}$

?=5