Question

250 (a-b)^3+2 .factorise it

Answer 1

=250 ( a-b) ^ 3 + 2

=2 ( 125 ( a-b) ^ 3 + 1)

=2 ( 5 ^ 3 ( a-b) ^ 3 + 1 ^ 3)

=2 ( ( 5a-5b) ^ 3 + 1 ^ 3)

we know that,

a^ 3 + b ^ 3= ( a + b) ( a ^ 2 + b ^2-ab)

=2 ( 5a - 5b + 1) ( ( 5a-5b) ^ 2 + 1- ( 5a-5b))

=2 ( 5a-5b + 1) ( 25a ^ 2 + 25b ^ 2-50ab + 1-5a + 5b)

=2 ( 5a-5b + 1) (25a ^ 2 +25b ^ 2-50ab-5a + 5b + 1)

Answer 2

Step-by-step explanation:

250(a-b)^3+2

2(125(a-b)^3+1)

2((5^3)(a-b)^3+1)

2((5a-5b)^3+(1^3))

2(5a-5b+1) ((5a-5b)^2-(5a-5b)×1+(1^2))

2(5a-5b+1) (25a^2-50ab+25b^2-5a+5b+1)