a bag contains 15 coins of 2 rupee and 5 rupee the total amount of the coin is rupees 45 how many coins of each find are there in the bag
Answers
Answered by
2
Let a be Rs. 2 Coin & b be Rs. 5 Coin
a + b = 15
And
2a + 5b = 45
Solving we get,
2(15-b) + 5b = 45
b = (45 - 30)/3
b = 5
hence
a = 10
a + b = 15
And
2a + 5b = 45
Solving we get,
2(15-b) + 5b = 45
b = (45 - 30)/3
b = 5
hence
a = 10
Answered by
1
let no.of coins of 2 be x
let no.of coins of 5 be y
x + y = 15
x = 15-y
also, 2x + 5y = 45
2(15-y) + 5y = 45
30-2y+5y = 45
3y = 15
y = 5 ( no.of coins of 5 )
x+5= 15
x = 10 (no.of coins of 2)
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let no.of coins of 5 be y
x + y = 15
x = 15-y
also, 2x + 5y = 45
2(15-y) + 5y = 45
30-2y+5y = 45
3y = 15
y = 5 ( no.of coins of 5 )
x+5= 15
x = 10 (no.of coins of 2)
may it help u ...
plz press brainliest...
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