Question

250
the shape of a garden is rectangular in the middle and semi circular
the ends as shown in the diagram. Find the area and the perimeter
T of this garden [Length of rectangle is
7m 20- (3.5+3.5) metres).
​

Answer 1

20-(3.5+3.5)
20-(7)
=-140

Answer 2

$\underline\bold\green{step \: by \: step \: explination}</p><p></p><p></p><p>$

Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

$l.b + 2 \times \frac{1}{2}\pi {r}^{2}$

$= (13 \times 7) {m}^{2} +$

$(2 \times \frac{1}{2} \times \frac{22}{7} \times 3.5 \times 3.5) {m}^{2}$

$= (91 + 38.5) {m}^{2} = 129.5 {m}^{2}$

Perimeter of the garden =2× length of rectangular portion + circumference of the circle

$= (2 \times 13 + 2 \times \frac{22}{7} \times 3.5)m$

$= (26 + 22)m = 48m$