Question

2500 CC of oxygen was burnt with 600cc of Ethane calculate volume of unused Oxygen and volume of carbon dioxide formed

Answer 1

2C2H6 + 7O2 ------>  4CO2 + 6H2O +Δ [equation]

Given:

C2H6 used = 600cc


C2H6                     O2
   2                          7    [ratio]                         
   600                      x

x = 600 x 7 /2
x = 2100cc [used oxygen]

So unused oxygen =  2500-2100  =  400cc

Volume of CO2 produced:


C2H6                          CO2
   2                                4       [ratio]
   600                            x

   x   =  600 x 4 / 2
   x  =  1200cc

Therefore 1200cc of CO2 is produced.


Hope it helps..........................

Answer 2

2 C2H6  + 7 O2 --->4 CO2 +6 H2O 

 ethane rqd = 2volume 

oxygen rqd = 7 volume

 therefore for 600 cc of ethane 

volume of oxygen rqd = 300 x 7 cc = 2100 cc 

volume of carbon dioxide formed will be =  4 volume = 4 x 300 cc = 1200 cc 

volume of unused oxygen left = 2500 - 2100 =400 cc