in an isosceles triangle the angle of top vertex is twice the sum of base angles find all exterior angles of triangle
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according to the problem
the angles of the isosceles triangle ABC are x,x,4x.
now,
x+x+4x=180
6x=180
x=30.
the interior angles of the triangle are
30,30,120
ext angle at A=30+120=150
lly at B=30+120=150
at C=30+30=60
the angles of the isosceles triangle ABC are x,x,4x.
now,
x+x+4x=180
6x=180
x=30.
the interior angles of the triangle are
30,30,120
ext angle at A=30+120=150
lly at B=30+120=150
at C=30+30=60
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