2500 cm3 of hydrogen is taken at S.T.P. The pressure of this gas is further increased by two and a half times (temperature remaining constant). What volume will hydrogen occupy now
Answers
Answered by
31
Hello friend!!
Rajdeep here...
P1 = x, P2 = 5x/2
T1 = y, T2 = y [constant]
V1 = 2500, V2 = ?
By gas equation,
P1V1/T1 = P2V2/T2
=> 2500x/y = 5x × V2/2 × y
=> 2500 = 5V2/2 [x and y on both sides are cancelled]
So V2 = 2500x2/5
= 500x2
= 1000cm³
Hope this helps..
Thanks???
Mention not....
Rajdeep here...
P1 = x, P2 = 5x/2
T1 = y, T2 = y [constant]
V1 = 2500, V2 = ?
By gas equation,
P1V1/T1 = P2V2/T2
=> 2500x/y = 5x × V2/2 × y
=> 2500 = 5V2/2 [x and y on both sides are cancelled]
So V2 = 2500x2/5
= 500x2
= 1000cm³
Hope this helps..
Thanks???
Mention not....
Answered by
2
Answer:
V1=2500cm3
P1=1atm
P2=1+2 1/2
=1+3/2
=5/2
P1V1=P2V2
P1V1 =V2
P2
1×2500 =V2
5/2
1×500×2= V2
1000 cm3 =V2
HOPE IT'S HELPS U MARK ME BRAINLIEST
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