Question

25025 = p^x1 ×q^x2×r^x3×s^x4 Find p,q,r,s x1, x2, x3, x4 by prime factorisation method​

Answer 1

Answer:

x4+x3+x2+x+1. =(x2+(12+√52)x+1)(x2+(12− √52)x+1). Explanation: This quartic has four zeros, which are the non-Real Complex 5 th ...

x4+x3+x2+x+1 =(x2+(12+√52)x+1)(x2+(12−√52)x+1) Explanation: This quartic has four zeros, which are the non-Real Complex 5th roots of 1, as we ...