(253,440)solve by euclid's division algorithm
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Solving HCF of (253,440) by Euclid's division algorithm
440 = 253*1 + 147
253 = 147*1 + 106
147 = 106*1 + 41
106 = 41*2 + 24
41 = 24*1 + 17
24 = 17*1 + 7
17 = 7*2 + 3
7 = 3*2 + 1
3 = 1*3 + 0
Last divisor is 1. So, HCF (253,440) is 1.
Thank you.
440 = 253*1 + 147
253 = 147*1 + 106
147 = 106*1 + 41
106 = 41*2 + 24
41 = 24*1 + 17
24 = 17*1 + 7
17 = 7*2 + 3
7 = 3*2 + 1
3 = 1*3 + 0
Last divisor is 1. So, HCF (253,440) is 1.
Thank you.
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