Question

256, 442 and 940 FIND THE HCF OF THE FOLLWING​

Answer 1

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Given:

3 numbers : 256, 442 and 940

To Find:

The HFC of the 3 numbers

Solution:

Find the product of its prime factors of 256:

256 = 2 x 2 x 2 x 2 x 2 x2 x 2 x 2

256 = 2⁸

Find the product of its prime factors of 442:

442 = 2 x 13 x 17

Find the product of its prime factors of 940:

940 = 2 x 2 x 5 x 47

940 = 2² x 5 x 47

Find the HFC of the 3 numbers:

256 = 2⁸

442 = 2 x 13 x 17

940 = 2² x 5 x 47

HFC is the common prime factors among the 3 numbers

⇒ HFC = 2

Answer 2

Step-by-step explanation:

Given:

3 numbers : 256, 442 and 940

To Find:

The HFC of the 3 numbers

Solution:

Find the product of its prime factors of 256:

256 = 2 x 2 x 2 x 2 x 2 x2 x 2 x 2

256 = 2⁸

Find the product of its prime factors of 442:

442 = 2 x 13 x 17

Find the product of its prime factors of 940:

940 = 2 x 2 x 5 x 47

940 = 2² x 5 x 47

Find the HFC of the 3 numbers:

256 = 2⁸

442 = 2 x 13 x 17

940 = 2² x 5 x 47

HFC is the common prime factors among the 3 numbers

⇒ HFC = 2