Question

256 gram of S8 react with 192 gram of O2 calculate mass of SO2 formed if the percentage yield is 50%​

Answer 1

Answer:

2.5g is the right answer

Answer 2

Answer:

192 g of SO2 is formed

Explanation:

Mol wt of S8 = 32x 8 = 256g

Molecular wt of O2 = 32g

S8 + 8O2 ---> 8SO2

Moles of oxygen in 192g of O2 = 192/32 = 6

1 mole of S8 + 8 moles of O2 = 8 moles of SO2

? moles of S8 + 6 moles of O2 = 6 moles of SO2

If yield is 50% then only 3 moles of SO2 is formed

1 mole of SO2 = 64g

3 moles of SO2 = 64g x 3 = 192g