Question

25a^2-4b^2+28bc-49c^2
​

Answer 1

Answer:

(5a-2b+7c)(5a+2b-7c)

Step-by-step explanation:

25a^2-4b^2+28bc-49c^2

=(5a)^2-{(4b^2-2(2b)(7c)+7c^2}

=(5a)^2-{2b-7c}^2

=(5a-2b+7c)(5a+2b-7c)

Hope this helps......

Answer 2

Answer:

(5a+2b-7c)(5a-2b+7c)

Step-by-step explanation:

25a^2 - (4b^2 - 28bc + 49c^2)

25a^2 - ((2b)^2 - 2(2b)(7c) + (7c)^2)

Using the identity:-

a^2 - 2ab + b^2 = (a-b)^2

25a^2 - (2b-7c)^2

Using the identity:-

a^2 - b^2 = (a+b)(a-b)

(5a)^2 - (2b-7c)^2

(5a+(2b-7c))(5a-(2b-7c))

(5a+2b-7c)(5a-2b+7c)

Hence, 25a^2-4b^2+28bc-49c^2 = (5a+2b-7c)(5a-2b+7c)

Hope it helps......