Question

25a^2 - 9b^2 + 12bc - 4c^2​

Answer 1

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★ ᴀɴsᴡᴇʀ:-

⛄ (5ᴀ - 3ʙ + 2ᴄ) (5ᴀ + 3ʙ - 2ᴄ)

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★ sᴛᴇᴘ-ʙʏ-sᴛᴇᴘ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ:-

⛄ 25a² -9b² + 12bc - 4c²

ᴇxᴛʀᴀᴄᴛ ᴛʜᴇ ɴᴇɢᴀᴛɪᴠᴇ sɪɢɴ ғʀᴏᴍ ᴛʜᴇ ᴇxᴘʀᴇssɪᴏɴ.

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↪25a² - (9b² - 12bc + 4c²)

ᴜsɪɴɢ ᴀ² - 2ᴀʙ + ʙ² = (ᴀ-ʙ)², ғᴀᴄᴛᴏʀ ᴛʜᴇ ᴇxᴘʀᴇssɪᴏɴ.

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↪25a² - (3b - 2c)²

ᴜsɪɴɢ ᴀ² - ʙ² = (ᴀ+ʙ)(ᴀ-ʙ), ғᴀᴄᴛᴏʀ ᴛʜᴇ ᴇxᴘʀᴇssɪᴏɴ.

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↪(5a - [3b - 2c] ) × (5a + [3b -2c])

ʀᴇᴍᴏᴠᴇ ᴘᴀʀᴇɴᴛʜᴇsᴇs.

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☞ (5a -3b + 2c) (5a +3b -2c)

ᴛʜᴇ ʀᴇϙᴜɪʀᴇᴅ ғᴀᴄᴛᴏʀɪᴢᴀᴛɪᴏɴ!

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Answer 2

★Question :

to find factorisation of :

25a² -9b² + 12bc - 4c²

★ solution :

25a² -9b² + 12bc - 4c²

= 25a² - (9b² - 12bc + 4c²)

[ ᴀ² - 2ᴀʙ + ʙ² = (ᴀ-ʙ)²] then ,

= 25a² - (3b - 2c)²

ᴜsɪɴɢ ᴀ² - ʙ² = (ᴀ+ʙ)(ᴀ-ʙ)

= (5a - [3b - 2c] ) × (5a + [3b -2c])

Rearrange the terms

= (5a -3b + 2c) (5a +3b -2c)

ᴛʜᴇ ʀᴇϙᴜɪʀᴇᴅ Answer !

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