Question

(25a square+10ac+c square)-49b square​

Answer 1

Answer:

($(25a^{2} + 10ac + c^{2} ) - 49 b^{2} \\\\=>  (5a^{2} +c^{2} )- 49b^{2} \\\\=> 5a^{2} -49b^{2}+ c^{2}$$formula used : (x^{2} +ab+ b^{2} ) = (a+b)^{2}$

you can also write $49b^{2}  = (7b^{2} )$

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(please ignore that A cap its just been added while putting the latex)

hope it helps :)

thanks :)

Answer 2

$\huge{\texttt{Answer \ :-}}$

$( {25a}^{2} + {c}^{2} \: + 10ac) \: - {49b}^{2}$

[Identity :- ${x}^{2}$ + ${y}^{2}$ + 2 xy = ${(a+b)}^{2}$ ]

${(5a + c)}^{2}$ - ${(7b)}^{2}$

[Identity :- ${x}^{2}$ - ${y}^{2}$ = (x + y) (x - y)

$<b>(5a + c + 7b) (5a + c - 7b)$