Physics, asked by anvithavaishnavee349, 3 months ago

25g of ice at -10°c is changed into superheated steam at 120°c by supplying 76000J of heat energy if the sp heat capacity of ice and steam is 2J/g°c and sp latent heat of ice is 336J/g calculate the sp latent heat capacity of steam​

Answers

Answered by samyak2501
1

Answer:

the specific latent heat capacity of steam is 3444 J/g.

Explanation:

The heat energy required to convert a mass of a substance from one phase to another is given by the formula:

Q = m × L

where Q is the heat energy, m is the mass of the substance, and L is the specific latent heat of the substance.

In this problem, we can use this formula to calculate the heat energy required to melt the ice and then to vaporize the resulting water into steam:

Heat energy to melt the ice = 25 g × 336 J/g = 8400 J

Heat energy to vaporize the water = 25 g × 2 J/g°C × (100°C - (-10°C)) + 25 g × 336 J/g = 79500 J

The total heat energy supplied is the sum of the heat energy required to melt the ice and vaporize the water:

Total heat energy supplied = 8400 J + 79500 J = 87900 J

The change in temperature of the ice and the steam is given by:

ΔT = 120°C - (-10°C) = 130°C

The specific heat capacity of the ice can be used to calculate the heat energy required to raise its temperature from -10°C to 0°C:

Heat energy to raise the temperature of the ice = 25 g × 2 J/g°C × (0°C - (-10°C)) = 500 J

The specific heat capacity of the steam can be used to calculate the heat energy required to lower its temperature from 120°C to 100°C:

Heat energy to lower the temperature of the steam = 25 g × 2 J/g°C × (120°C - 100°C) = 1000 J

The total heat energy required to raise the temperature of the ice and lower the temperature of the steam is:

Total heat energy for temperature change = 500 J + 1000 J = 1500 J

The specific latent heat capacity of steam is given by:

L = (Total heat energy supplied - Total heat energy for temperature change) / (mass of steam)

mass of steam = mass of ice = 25 g

Substituting the values, we get:

L = (87900 J - 1500 J) / (25 g) = 3444 J/g

Therefore, the specific latent heat capacity of steam is 3444 J/g

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