Question

25j^2-10j+1 fund the zeroes of the polynomial

Answer 1

Hey friend..!! here's your answer
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hope this attachment will help you

Answer 2

25j² -10j +1

25j²-5j -5j +1

Commonly taking out

5j (5j-1) -1 (5j-1)

(5j-1)(5j-1)

j = $\frac{1}{5}$ ,$\frac{1}{5}$