Question

25n^5-36y^2 find please​

Answer 1

Answer:

Answer: By factorization of \bold{25 x^{2}-10 x+1-36 y^{2}}25x

2

−10x+1−36y

2

,we get ((5x-1) + 6y) ((5x-1) - 6y)

25 x^{2}-10 x+1-36 y^{2}=(5 x)^{2}-2(5 x)+1^{2}-(6 y)^{2}25x

2

−10x+1−36y

2

=(5x)

2

−2(5x)+1

2

−(6y)

2

We know that by formula, (a-b)^{2}=a^{2}+b^{2}-2ab(a−b)

2

=a

2

+b

2

−2ab

(5 x)^{2}-2(5 x)+1^{2}(5x)

2

−2(5x)+1

2

can be written as (5 x-1)^{2}(5x−1)

2

25 x^{2}-10 x+1-36 y^{2}=(5 x-1)^{2}-(6 y)^{2}25x

2

−10x+1−36y

2

=(5x−1)

2

−(6y)

2

We know that by formula, a^{2}-b^{2}=(a+b)(a-b)a

2

−b

2

=(a+b)(a−b)

Hence 25 x^{2}-10 x+1-36 y^{2}25x

2

−10x+1−36y

2

= ((5x-1) + 6y) ((5x-1) - 6y)

Step-by-step explanation:

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Answer 2

Answer:

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