Question

26) 4 men throw a die each simultaneously. Find the probability that at least 2 people get the same number

Answer 1

we will find probability that all get different numbers

= 6*5*4*3/6*6*6*6

= 5/18

here favourable outcome = 6*5*4*3

since first person have all six choice of number but second person have only 5 choice cos can't get the same number that first person got and similarly for third and fourth

now probability that at least 2 people get same = 1- (none get the same)

= 1-(5/18)

= 13/18