Question

26) A boy's age is one-fourth that of his father.
After 24 years the boy will be half the age of
his father. Find their present ages.
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Answer 1

Answer:

Their present ages:

• Boy's age = 12 years
• His father's age = 48 years

Step-by-step explanation:

Given that:

• A boy's age is one-fourth that of his father.
• After 24 years the boy will be half the age of his father.

To Find:

• Their present ages.

Let us assume:

• Boy's present age be x.
• His father's present age = 4x

After 24 years:

• Boy's age = x + 24
• Father's age = 4x + 24

Finding their present ages:

According to the question.

⟶ 2(x + 24) = 4x + 24

⟶ 2x + 48 = 4x + 24

⟶ 4x - 2x = 48 - 24

⟶ 2x = 24

⟶ x = 24/2

⟶ x = 12

Their present ages:

• Boy's age = x = 12 years
• His father's age = 4x = (4 × 12) = 48 years

Answer 2

Given :-

A boy  age is one-fourth that of his father.  After 24 years the boy will be half the age of  his father.

To Find :-

Present ages

Solution :-

Let the present age of father be x

Age of son = x/4

Now

x/4 + 24 = x + 24/2

x + 96/4 = x + 24/2

2(x + 96) = 4(x + 24)

2x + 192 = 4x + 96

4x - 2x = 192 - 96

2x = 96

x = 96/2

x = 48 years

Age of son = 48/4 = 12 years